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Subject: A tricky xref problem
Hi all, I wonder if there is a way to extract a text string and pass it as a value for the <xref linkend=""/> expression. For example, when I write: Some text text text (see ref=[sect_test]), I would like to take the text within the [ ] delimiters and pass it as a value for the linkend attribute of the xref element called in my customized table template. The reason for this special workaround is that I've created a custom template that enables you to add a table row with its entries using one command, like so: <table> ... <row entry1="red" entry2="blue" entry3="black"/> -which saves a lot of typing. So, if I wish to add a reference to some section from within entry1, I can't write: <row entry1="red (refer to <xref linkend="sect_test"/>)" entry2="blue" entry3="black"/> I need somehow to customize my table template that says something like: ... <xsl:for-each select="row"> <row> <xsl:if test="$entry1"> <entry> <xsl:value-of select="@entry1"/> <xsl:if test="contains('xref')"> <xref> <xsl:copy-of select="@*"/> <xsl:attribute name="linkend"> <xsl:copy-of select="@*"/> <xsl:value-of select="<extracted_text_string>"/> </xsl:attribute> </xref> </xsl:if> </entry> </xsl:if> ... </row> </xsl:for-each> ... Please, advise me how to extract the text string from within [ ] delimiters to pass it as a value for the <xref> expression. Thanks a lot in advance!!! Best wishes, Nancy |
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